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(9)/(x^2+3x)-(1)/(x)=(2)/(x+3)
We move all terms to the left:
(9)/(x^2+3x)-(1)/(x)-((2)/(x+3))=0
Domain of the equation: (x^2+3x)!=0
x∈R
Domain of the equation: x!=0
x∈R
Domain of the equation: (x+3))!=0We calculate fractions
x∈R
(9x^2*()/((x^2+3x)*x*(x+3)))+(-1*(x^2+3x)*(x+3)))/((x^2+3x)*x*(x+3)))+(-(2*(x^2+3x)*x)/((x^2+3x)*x*(x+3)))=0
We calculate terms in parentheses: +(9x^2*()/((x^2+3x)*x*(x+3))), so:
9x^2*()/((x^2+3x)*x*(x+3))
We multiply all the terms by the denominator
9x^2*()
Back to the equation:
+(9x^2*())
We calculate terms in parentheses: +(-1*(x^2+3x)*(x+3)))/((x^2+3x)*x*(x+3)))+(-(2*(x^2+3x)*x)/((x^2+3x)*x*(x+3))), so:
-1*(x^2+3x)*(x+3)))/((x^2+3x)*x*(x+3)))+(-(2*(x^2+3x)*x)/((x^2+3x)*x*(x+3))
We add all the numbers together, and all the variables
-1*(x^2+3x)*(x+3)))/((x^2+3x)*x*(x+3)))+(-(2*(x^2+3x)*x)/((x^2+3x)*x*(x
We multiply all the terms by the denominator
-1*(x^2+3x)*(x+3)))+3x*x*x*((x^2+3))+(-(2*x^2*((x^2+3x)*x)+3x*x*x*((x^2
Wy multiply elements
3x^4*x-1*(x^2+3x)*(x+3)))+3x*x*x*((x^2+3))+(-(2*x^2*((x^2+3x)*x)
We do not support expression: x^4
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